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find x 10^x = 5
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x = log(5)
That logarithm is base 10, so i didn't write the base.
log(5) = 0.698970004
More specifically, the reasoning fo rthe answer is that taking the base 10 logrithm of both sides gives you \[x*\log(10) = \log(5)\] and \[\log(10) = 1\] so you're left with \[x = \log(5)\]
Yes, a^x = y is the same as x = log<base a>(y) "A to the x equals y" is the same as "x equals logarithm, base a, of y" Here's more *readable* ;) info: http://oakroadsystems.com/math/loglaws.htm
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