Question

a^2b^3c = 256/27 find the min value of a+b+c

Answer 1

Take the numbers as a/2,a/2,b/3,b/3,b/3,c
apply AM>= GM you will get the answer

Answer 2

Let us say a,b,c are three numbers in AP
then AM = (a+b+c) /3
and if a,b,c are three numbers in GP
GM = (a*b*c)^1/3

Answer 3

does it make sense to you?