Find the total number of values of 'x' in : 2^x = x^2 ?
1) 3 values 2postivie 1 negative
2) 2 values both positive
3) 2 values 1 negative and 1 positive
4) 1 positive
5) 1 negative
6) 3 values

Question

Find the total number of values of 'x' in : 2^x = x^2 ?
1) 3 values 2postivie 1 negative
2) 2 values both positive
3) 2 values 1 negative and 1 positive
4) 1 positive
5) 1 negative 
6) 3 values

anonymous · Answer

2,4 and -0.9

anonymous · Answer

oh how u found this

anonymous · Answer

wolframalpha

anonymous · Answer

Ok can u explain me please

anonymous · Answer

go to http://www.wolframalpha.com/input/?i=2^x%20%3D%20x^2&t=crmtb01

anonymous · Answer

thanks very much

anonymous · Answer

I can see the 2 and the 4, how does the -0.9 work?

anonymous · Answer

its actually more of something arnd -0.76

anonymous · Answer

Naughty Wolfram..

anonymous · Answer

If you put 2^{-x} into Wolfram it gets it right  with a sign change.

anonymous · Answer

Problem here is f is 2^x - x^2 is not analytic so no straightforward algebra to the complete solution..

anonymous · Answer

problem doesn't ask for a solution.  just asks what they look like. i think your teacher wanted you to graph and see where they intersect, rather than find the actual numbers (even though 2 and 4 are rather clear)