simplify (7x^2-9)-(8+3x)-(2x^2-8x)
So again, start looking at common terms. You have 7 x-squareds at the front, any other x-squareds?
3x
Those are xes, not x-squareds.
You have 3 different 'types' of terms here. You have terms of 'ones' (the ones with no x), terms of 'xes' (the ones with an x) and terms of 'x-squareds' (the ones with x^2)
So looking at your expression you have 7 x-squareds, and you subtract 2 x-squareds. Since there are no other x-squareds, how many will you have at the end?
5x
5x^2
Ok, so now that the hard part is done, look at the x terms. What do you see?
Try to set it up the way I was.
5x^2-11x-17
Nicely done. The only problem is the -11x in the middle.
Because you start with a -3x from the second set of parens. Then you subtract a -8x from the last set. -3x - -8x =?
so then it would 5x^2+5-17
5x^2 + 5x - 17 is correct.
thanks
Join our real-time social learning platform and learn together with your friends!