A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in! Her father immediately jumped on his scooter to try and track her down and tell her the good news. Riding at a breezy 15 miles per hour, at what time will her father catch up to her?

What is a reasonable first step in solving this problem?

A. Determine how many days the daughter has to train

Question

A young equestrian loved to ride her horse all day long, dreaming of the day she would ride in the Kentucky Derby. One day in early April, she left home at 10:00 am and rode her stallion at a nice, steady 10 miles per hour away from her house. At noon a call came in from the Derby saying she was in! Her father immediately jumped on his scooter to try and track her down and tell her the good news. Riding at a breezy 15 miles per hour, at what time will her father catch up to her?

What is a reasonable first step in solving this problem?

A. Determine how many days the daughter has to train

anonymous · Answer

1. determine how far from the house the young equestrian is (20 miles)
2. determine the difference in speed between her and her father (5 miles per hour)
3. determine how long it will take to cover the distance in 1. at the speed in 2 (4 hours)
4. Add the time from 3 to the current time of noon (4:00 PM)

anonymous · Answer

coincidental that a person with your user name would be asking a question about equestrians?