Question

A carpenter is building a rectangle room with a fixed perimeter of 172ft. What dimensions would yield the maximum area? What is the maximum area?

The length that would yield the maximum area is ? ft

Answer 1

perimeter of a rectangle is to add up the lengths of the sides
so since there are 2 lengths n 2 widths then u kno that if we called the width w and the length l then the perimeter equals 2 times the addition of the length and the width:
2(l+w)=perimeter and u kno the peremeter is 172
so:
2(l+w)=172

Now the are equals length times width
so:
A=lw

now solve the first equation for l
2(l+w)=172
l+w=86
l=86-w

substitute this l for the l in the 2nd equation

A=lw
A=(86-w)w
A=86w-w^2

Now find the maximum

w=-(86)/(2*-1)
w=43
so l=43

and the best dimensions is a square with length 43

Answer 2

43 feet is the answer

Answer 3

then i did it right :)

Answer 4

wide?

Answer 5

what?

Answer 6

what is the width? I tried 86 but that was not right

Answer 7

its a square. the length and the width r the same.
l=w=43

Answer 8

maximum area? please

Answer 9

43*43 sq ft.