I need help write hyperbola equation 4x^2-26y^2+10=0
\[(x ^{2}/a ^{2})-(y ^{2}/a ^{2)}=1\]
\[4x^2-26y^2=-10\]
\[\frac{4x^2-26y^2=-10}{-10}\]
The should be no coefficient (or, rather, a 1 in front of x^2 and y^2. You can leave the 10 on the LHS for the moment, so you don't have to deal with negative. But first divide by (4)(26)
yes,but is decimal right?
frist division by 4?
\[x^2-\frac{26y^2}{4}=\frac{-10}{4}\]?
I use too no problem to write equation, but this number seem not even, Make me confuse
26/4 is decimal
move 10 to left hand side,than (4*26)+(-10) ?
Yes, the numbers are not coming out like squares, it usually works out. Make sure you wrote down the problem right.
yes, I did
I never see like dis problem before,I will send you the page,check number 9
Well, the question doesn't say put in form of hyperbola. It asks is it parabola, circle, ellipse, or hyperbola.
but I write befor graph
I can state is hyperbola, but I need to know x and y I can graph
Yeah, it is a hyperbola, but the numbers are complicated. I graphed it on wolfram http://www.wolframalpha.com/input/?i=4x^2-26y^2%2B10%3D0
ty
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