2/1sqrt2^3=?
rewrite it using the equation button below
yeah, it's unclear as written. Either write with the equation editor or use parens to make it clear.
2/(1/sqrt2)^3=?
2*2sqrt(2) = 4sqrt(2) That's what I got.
\[\frac{2}{(\frac{1}{\sqrt{2}})^3}\]???
\[2 \div \frac{1}{(\sqrt{2})^3} = 2 \times (\sqrt{2})^3 = 4\sqrt2\]
That's how I interpreted it, Hick.
answer 4sqrt2...nicely done smooth math, dhatrad..
how does 2 x (sqrt2)^3 = 4sqrt2?
\[\sqrt{2}\times\sqrt{2}\times\sqrt{2}=2\sqrt{2}\] throw in the extra 2 and you get \[4\sqrt{2}\]
2/ (1/sqrt2)^3 =2/ ((1/sqrt2)(1/sqrt2)(1/sqrt2)) = 2/ ((1/2)(1/sqrt2)) = 2/ (1/2sqrt2) = 2 * (2sqrt2/1) = 2*2sqrt2 = 4sqrt2
sqrt2^3 = sqrt 2 x sqrt 2 x sqrt 2 = 2 sqrt 2
Some part of that still confusing you? Is it how they end up multiplying? When you divide by a fraction, it's the same as multiplying by the reciprocal of that fraction.
idk, its just not clicking, its the multi. the sqrts i dnt get, how does sqrt2^3 = 2sqrt2?
do you understand that \[(\sqrt2)^3 = \sqrt2 \times \sqrt 2 \times \sqrt 2\] ?
yes
And do you see that sqrt2*sqrt2 = 2?
do you understand that \[\sqrt2 \times \sqrt 2 = 2\] ?
yes
By definition, sqrt2 is the number that, when multiplied by itself, gives 2.
ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
so, \[\sqrt2 \times \sqrt 2 \times \sqrt2 = 2 \times \sqrt2 = 2\sqrt2\]
wow, gotcha! i appreciated fellas thank u!
no problem
My pleasure.
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