Question

Why McLaurin of f(x)= e^(cos(x^3)) is e - (ex^6)/6?
Why there's e?

Answer 1

because is the equation of E=1

Answer 2

the equation of e =1?
Sorry but I don't understand what you mean.

Answer 3

NO ,, because the E is equal to 1 the answer is (cosx1(e)

Answer 4

the series goes like
f(x)=f(0)+f'(0)*x+f''(0)*x^2/2!+f'''(0)*x^3/3!+.....
so
f(0)=e^(cos0^3)=e^(cos0)=e^(1)=e

Answer 5

cos0=1

Answer 6

hector do you understand why the constant e is there now?

Answer 7

oh that's clear. Thanks you.

Answer 8

thanks :)

Answer 9

what