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Mathematics 18 Online
OpenStudy (anonymous):

picture attached

OpenStudy (anonymous):

OpenStudy (anonymous):

scratch #23

OpenStudy (anonymous):

for 20. XY = WZ = 10 (bcoz equidistant chords r equal)

OpenStudy (amistre64):

since gh= 80; f = 40 .... that leaves 50 for "e"

OpenStudy (amistre64):

the measure of x = m/2 but they say that 2m+m=360 3m = 360 m = 360/3 = 120 x = 60

OpenStudy (amistre64):

xy = wz = 10

OpenStudy (amistre64):

cant recall #22 tho ...

OpenStudy (anonymous):

which one is for which problem?

OpenStudy (anonymous):

thanks!! never mind about the last reply

OpenStudy (amistre64):

79.5 if i did the math right :)

OpenStudy (amistre64):

OpenStudy (amistre64):

:)

OpenStudy (anonymous):

for 22. x = 75 deg

OpenStudy (anonymous):

how do you do that harkirat?

OpenStudy (anonymous):

wait...I'll show u

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

?

OpenStudy (anonymous):

As per my figure I first calculate angleY We use the theorem "The measure of the angle formed by two chords that intersect inside the circle is ½ the sum of the chords' intercepted arcs." so y = 1/2 (80+130) = 1/2(210) = 105 now angleX + angleY = 180 deg ------linear pair of angles so angleX = 180-angleY = 180 - 105 = 75 deg Pls check and tell if it is clear enough.....

OpenStudy (anonymous):

We can also solve it like this... since a circle = 360 deg. the sum of the three angles marked is 80 + 60+ 130 = 270 so angle for the remaining unmarked arc is 360 - 270 = 90 so x = 1/2 (90+60) = 1/2(150) = 75 deg

OpenStudy (anonymous):

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