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OpenStudy (anonymous):
OpenStudy (anonymous):
scratch #23
OpenStudy (anonymous):
for 20.
XY = WZ = 10 (bcoz equidistant chords r equal)
OpenStudy (amistre64):
since gh= 80; f = 40 .... that leaves 50 for "e"
OpenStudy (amistre64):
the measure of x = m/2 but they say that
2m+m=360
3m = 360
m = 360/3 = 120
x = 60
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OpenStudy (amistre64):
xy = wz = 10
OpenStudy (amistre64):
cant recall #22 tho ...
OpenStudy (anonymous):
which one is for which problem?
OpenStudy (anonymous):
thanks!! never mind about the last reply
OpenStudy (amistre64):
79.5 if i did the math right :)
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OpenStudy (amistre64):
OpenStudy (amistre64):
:)
OpenStudy (anonymous):
for 22.
x = 75 deg
OpenStudy (anonymous):
how do you do that harkirat?
OpenStudy (anonymous):
wait...I'll show u
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OpenStudy (anonymous):
thank you!
OpenStudy (anonymous):
?
OpenStudy (anonymous):
As per my figure I first calculate angleY
We use the theorem "The measure of the angle formed by two chords that intersect inside the circle is ½ the sum of the chords' intercepted arcs."
so y = 1/2 (80+130) = 1/2(210) = 105
now angleX + angleY = 180 deg ------linear pair of angles
so angleX = 180-angleY = 180 - 105 = 75 deg
Pls check and tell if it is clear enough.....
OpenStudy (anonymous):
We can also solve it like this...
since a circle = 360 deg.
the sum of the three angles marked is 80 + 60+ 130 = 270
so angle for the remaining unmarked arc is 360 - 270 = 90
so x = 1/2 (90+60) = 1/2(150) = 75 deg