Ok last one then i will do the rest....please help thanks in advance....http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_%280%29%5E%281%29%20x%5E%282%5C%2F7%29%20dx

Question

amistre64 · Answer

teh 0 is pointless and the rest is just oned up so ,,,

x^(2/7) ints up to x^((2+7)/7)*(7/(2+7))

amistre64 · Answer

7/9 it looks like

anonymous · Answer

$$7/9x ^{9/7}$$$$\left\{ 7/9(0^{9/7} \right\}-\left\{ 7/9(1^{9/7} \right\}$$

anonymous · Answer

ok im trying to understand where 9 come from...

amistre64 · Answer

2/7 + 7/7 = (2+7)/7 = 9/7 for the exponent; invert it for the coeff

anonymous · Answer

2/7+1=9/7

amistre64 · Answer

power rule for integration; add 1 to the exponent

anonymous · Answer

ok so you basically added and whole number 7/7=1 to the problem?

anonymous · Answer

yes i remember that

amistre64 · Answer

well; thats what the exponent goes to; and then you flip it for the coefficient

anonymous · Answer

ok ok..now i get it thanks everyone : ) now i will do the rest myself...thanks again

amistre64 · Answer

yep :)

anonymous · Answer

welcome