The graph I attatched has the same sshape as the graph of g(x)=x^2, but it's shifted down five units and to the left four units. Complete it's equation?
F(x)=

Question

anonymous · Answer

attachment

anonymous · Answer

from vertex?

anonymous · Answer

I believe so

anonymous · Answer

$$f(x)=(x+8)^2-10$$

anonymous · Answer

that wasn't right according to my cyberschool, so maybe it's not from the vertex?

anonymous · Answer

if the original graph is f(x) = x^2, and its shifted down five units and left four units then we should get:
$$f(x) = (x+4)^{2}-5$$

anonymous · Answer

shifted down five units=-5-5=-10
 and to the left four units= -4-4 =-8
(x+8)^2-10

anonymous · Answer

This is the general equation for a parabola:
$$f(x) = (x-h)^{2}+k$$
where the vertex of the parabola is the point (h,k).  Your original vertex is at (0,0), your new one is at (-4, -5) which is the shift down by 5, and to the left by 4.  so h = -4, k = -5, and you plug that into the formula above.