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Mathematics
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Multiply and simplify
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\[3y^5/8r3*64r^6/9y\]
8^3
so:\[\frac{3y^5}{8r^3} \times \frac{64r^6}{9y}\]???
what does your followup "8^3" mean?
Sorry I was doing a different problem yes the equation you have set up right I was just fixing a typo I wrote on the equation
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OK, so:\[\frac{(3y^5)(64r^6)}{(8r^3)(9y)}\]then cancel 3y from both:\[\frac{(y^4)(64r^6)}{(8r^3)(3)}\]then cancel 8r^3 from both:\[\frac{(y^4)(8r^3)}{(3)}=\frac{8y^4r^3}{3}\]
so you just see what goes int 9 which is 3 the but how did you get 8y^4
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