Mathematics
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OpenStudy (anonymous):
Give exact and approximate solutions to three decimals place.
x^2+18x+81=1
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jhonyy9 (jhonyy9):
- this is (x+9)*2 =1 --- x+9=1 --- x=-8
64-144+80=0
OpenStudy (anonymous):
ok so what are the decimals I am confused?
jhonyy9 (jhonyy9):
have not decimals
OpenStudy (anonymous):
it is asking for exact answer then in form i ?
OpenStudy (anonymous):
so i put 0
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jhonyy9 (jhonyy9):
here you not will get i never - complex numbers like solution
jhonyy9 (jhonyy9):
but now i see that is again right solution -10 too
jhonyy9 (jhonyy9):
because -10 +9=(-1)*2 =1
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
this one is the same (x+7)^2=64
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jhonyy9 (jhonyy9):
so in finaly we can seeing that there are two solutions -10 and -8
OpenStudy (anonymous):
r we on the first or second one
jhonyy9 (jhonyy9):
here in the secongd equation you have (x+7)*2 = 64 = 8*2 - so if you make radical from both sides you get x+7=8 --- x=1
OpenStudy (anonymous):
k
OpenStudy (anonymous):
so x=1
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jhonyy9 (jhonyy9):
yes
jhonyy9 (jhonyy9):
hope so much that i have helped to you and that all is clearly
OpenStudy (anonymous):
yes I have some more you want to help me with those too please
jhonyy9 (jhonyy9):
- for you being sure rigth in solutions you need to make probe
jhonyy9 (jhonyy9):
ok let's go
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OpenStudy (anonymous):
Determine the nature of the solution if the equation
y^2= 2/3 y+ 3/7
the y is with the whole 2/3 not just the 3
OpenStudy (anonymous):
one real solution?
two non- real solution?
two real solution?
OpenStudy (anonymous):
multiply choice here
jhonyy9 (jhonyy9):
please us parentheses
OpenStudy (anonymous):
y^2=(2/3y)+ (3/7)
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jhonyy9 (jhonyy9):
y*2 = 2/3y +3/7 what is the denominator common ?
OpenStudy (anonymous):
the y is with the whole (2/3) not just the 3
OpenStudy (anonymous):
21
jhonyy9 (jhonyy9):
i want to make you understand clearly
jhonyy9 (jhonyy9):
why 21 ?
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jhonyy9 (jhonyy9):
what are there like denominators ?
OpenStudy (anonymous):
7*3=21
3*7=21
that is the closest they have togather
jhonyy9 (jhonyy9):
and y there not is ?
jhonyy9 (jhonyy9):
becaus eyou have wrote 2/3y and not 2y/3
OpenStudy (anonymous):
I do not understand what you are asking?
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OpenStudy (anonymous):
y is with the whole fraction 2/3 I am not sure how to write other then
2
----y
3
jhonyy9 (jhonyy9):
how i have wrote to you before this you can write 2y/3
OpenStudy (anonymous):
ok
jhonyy9 (jhonyy9):
this is clearly ?
OpenStudy (anonymous):
yes!
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jhonyy9 (jhonyy9):
if yes what is the denominator common ?
jhonyy9 (jhonyy9):
ok 21 and in this case you need multiply the first term with ?
OpenStudy (anonymous):
I still am getting 21! Is that not correct or should it be 21y
jhonyy9 (jhonyy9):
ok yes is correct than y not is in denominator is 21
OpenStudy (anonymous):
ok
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jhonyy9 (jhonyy9):
and now how you will continue ?
OpenStudy (anonymous):
so 21 is the denominator?
jhonyy9 (jhonyy9):
if the denominator common is 21 what you need to do ?
jhonyy9 (jhonyy9):
multiplie the first term with ?
jhonyy9 (jhonyy9):
if you have y*2 =2y/3 +3/7
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jhonyy9 (jhonyy9):
because y*2 have denominator 1 you need to multiplie this term with 21
jhonyy9 (jhonyy9):
this is clearly ?