Question

integrate x^3dx/(x^2-a^2)^3
.... thanks

Answer 1

Geez this is a long one....

Answer 2

r u done with this ....or should i give try?

Answer 3

I posted the solution already

Answer 4

:)

Answer 5

could u try?

Answer 6

@heromiles: is that the answer already??

Answer 7

yeah y don't u add and subtract a^3 and then try solvin it

Answer 8

lol thats a copy from wolframa

Answer 9

also you can just sub u^2 =x^2 -a^2

so 2u du = 2x dx

Answer 10

u du = x dx

so = [(u^2+a^2) /(u^6) ] u du

Answer 11

= \[= \int\limits \frac{u^2+a^2}{u^5} = \int\limits( u^{-3} + a^2 u^{-5} )du \]

Answer 12

\[= -\frac{1}{2u^2} - \frac{a^2}{4u^4} +C = - \frac{1}{ 2(x^2-a^2)} - \frac{a^2}{4(x^2-a^2)^2} +C\]

Answer 13

which is equivalent to the answer wolframa gives, but its 10times faster, didnt involve cheating and is alot more elegant :)