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need help with finding the domain of a function.. g(x)=x+7 over x^2-16
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x cannot = 4
or -4
be careful here. you need to solve \[x^2-16=0\] and there are two solutions, namely 4 and -4
x can't be 4 or -4
I forgot the +/- symbol
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the answer has to be expressd in interval notation
(infinity, -4) (-4,4)(4, infinity)
thank you for your help!
Or like this: \[x \in (-\infty,-4) \cup (-4,4) \cup (4,\infty)\]
ooh that looks nice!
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is that \[x\in \]
got it on the first try
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