Can some one please give me directions on how this g(x) = ex -4
Description of transformation:
Equation(s) for the Horizontal Asymptote(s):
y-intercept in (x, y) form

Question

Can some one please give me directions on how this g(x) = ex -4
Description of transformation: 
Equation(s) for the Horizontal Asymptote(s): 
y-intercept in (x, y) form

anonymous · Answer

The equation of the horizontal asymptote for the equation$$f(x)=e^x$$is the line y=0.  So if we shift the graph down by 4 units, we get the equation $$g(x)=e^x-4$$Every point on the entire graph is shifted down by 4 units, which means our horizontal asymptote is now at y=-4.

To find the y-intercept for any equation, let x=0 and solve for y.  $$y=e^0-4$$$$y=1-4=3$$This gives the coordinates (0,-3) for the y-intercept.