Fun problem: Lets say you have a bag full of 75 red and 75 black marbles, and you are told to pull out 2 at a time. The rules are, if you pull out 2 of the same color, you toss them away, but if you pull out different colors, you toss the black and put the red back in the bag. You do this until only one ball is left. What is the probability of the last ball being red?

Question

Fun problem: Lets say you have a bag full of 75 red and 75 black marbles, and you are told to pull out 2 at a time. The rules are, if you pull out 2 of the same color, you toss them away, but if you pull out different colors, you toss the black and put the red back in the bag. You do this until only one ball is left.  What is the probability of the last ball being red?

anonymous · Answer

greater than that of the black one:P

anonymous · Answer

i think, haha, I hate probability

anonymous · Answer

joemath, stop pulling difficult questions you already know the answer to out of your math book, lol

anonymous · Answer

these are just for fun =/

anonymous · Answer

I'm going to try to find the answer

anonymous · Answer

cool :)

zarkon · Answer

1

anonymous · Answer

Correct! there really isnt any calculation involved, you just need to think about how the red balls leave the bag.  They can only leave in pairs, but there are 75 of them. So there is no way for the last red ball to ever get out; the last ball will always be red :)