Question

If the temperature decreases, the frequency of the tuning fork
a. increases
b. decreases
c. no change
d. none of these

Answer 1

and how are time and temperature related? :s

Answer 2

i'm sorry u'l have to wait a little longer fr this question.. i 'm not good with oscillations :(

Answer 3

You got um an hour and a half :p

Answer 4

maybe

Answer 5

can't say its 12pm here

Answer 6

i mean 12 am

Answer 7

11 45 here, sorry i usually study at night

Answer 8

while i m struggling with question .. u can get ne else like amistre and all.. they will be more helpful..

Answer 9

okay

Answer 10

see i've go this formula for volume expansion delta v = beta *int volume *delta time
delta for diiference and int fr initial

Answer 11

can u rlate it with mass

Answer 12

beta is the const for linear expansion

Answer 13

I am in grade 12. Should I be knowing this? O_O

Answer 14

well me too :).... but its in the book university physics.. u must have heard abt it

Answer 15

yeah and there's a reason it's "university" physics :p

Answer 16

:) but most of the text matches with india's syllabus for 11 and 12

Answer 17

Ahaan i'll check it out then

Answer 18

http://www.isb.ac.th/HS/JoP/vol5iss1/Papers/3TuningFork.pdf

Answer 19

it might help u

Answer 20

So when temperature increases, Young's modulus decreases, and so frequency decreases?

Answer 21

yes

Answer 22

It has been shown that the temperature affects the frequency of a tuning fork in a negative
exponential relationship, as shown in equation 2. Also, when aluminum is heated to nearly 600°
Kelvin, Young’s Modulus returns to its original value after the aluminum cools again. Finally, it
was shown that the frequency of a tuning fork can be used to find Young’s Modulus at high
temperatures given a known value for Young’s Modulus.

Answer 23

What if the temperature is decreased? =/

Answer 24

if temp is derease the e^-kt becomes less and subtraction is less

Answer 25

so tuning is more

Answer 26

that means frequency increases, right?

Answer 27

yes

Answer 28

great :) thanks

Answer 29

thanks... :) it helped me too.