Question

Solve sin2x + 2sinx = 0 for 0 ≤ x < 2π.

Answer 1

Now here we will have 2 equation
cosx +1 =0
cosx=-1
x=pi
sinx=0
x=pi or 0

Answer 2

2 sinx cosx + 2 sinx = 0

Answer 3

sin2x+2sinx=0

use sin2x =2sinx.cosx

2sinx[cosx+1]=0

=> either sinx= 0 or cosx+1=0

solce for either cae nd get the answer :)

Answer 4

sin x = 0 or cos x = -1.