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Mathematics 8 Online
OpenStudy (anonymous):

can someone help me with this intergration: sin2x

OpenStudy (amistre64):

(sin(x))^2 by chance?

OpenStudy (amistre64):

or sin(2x) ?

OpenStudy (anonymous):

the second one i believe

OpenStudy (amistre64):

do you recall what sin derives from?

OpenStudy (anonymous):

well, cosx gives us -sinx

OpenStudy (amistre64):

good; so -cos(2x) derives to sin(2x), almost, what happens in teh process?

OpenStudy (amistre64):

think chain rule

OpenStudy (anonymous):

yes, the 2x has to also get defferintiates , to 2 right

OpenStudy (amistre64):

correct; so we need to get rid of it when it comes out -cos(2x) ------- will take care of it 2

OpenStudy (anonymous):

so, we will be able to compenstae fo the chain rule in all integration problems by dividing what the argument differntiates to

OpenStudy (amistre64):

its a good rule of thumb ... and will carry you far yes

OpenStudy (anonymous):

oka, thanks

OpenStudy (anonymous):

do you know any website where i can get somemore practive problems of integration involving the chain rule

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