we are working a problem and we are to -8.620689 In (.91) We were wondering how do you put it into a TI-84 Plus?
-8.620689*ln(.91)
Hi! Good to see u again. I will try that real quick
when I do that, I get .813023037
the answer starts with 19
If the answer starts with 19 I don't think that you have the right question.
I will give you the question, so maybe that will make it easier
t=-1/k Ln (1-c/m) and the formula is t=-1/k Ln (1-c/m)
The question is: if mc's the theoretical maximum charge that a battery can hold and k is a positive that depends on the battery and the charger, the length of time + (in minutes) required to charge the battery to a given level c is given by....formula above
ok..
I don't see where those numbers came from though.
it is the answer in the book: 19.8 we are practicing on the cal for an upcoming test.
No no, I mean the numbers .91 and -8.620689
oh. How would you work the problem?
I don't know? I haven't seen what the problem is.
the first problem is the "problem" t=-1/k Ln (1-c/m)
we need to know how to enter on the cal a problem like -40 Ln (0.1) to get the answer 92.10340372
ln .1 enter *-40 enter
or just -40*ln(.1)
I think the 84 has parens around the arguments of functions.
Thank you!
Yea! God bless
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