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solve for X: log base 2 (2/X) = 3 + log base 2 X
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I get x=1/2. Your second line in the previous post doesn't follow. They are multiplied not added.
how did you get 1/2 makaze?
(why i can't give out medal)
the answer is suppose to be x = 1/2
I'll try to explain...
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I got 1/2
sorry for the delay, but im a little bit tired
get it?
First you get log2(2)-log2(x)=3+log2(x), take the log2(2)=1 so you get -2=2log2(x) so after dividing by 2 you simply have 2^(-1)=x=1/2
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ok I have to go. hope you understand what I posted. I have to sleep a little bit.
thanks
after i divide by 2 i get -1 = log2(x)
and then 2^(-1) = x
got it thank you
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