Make "l" the subject of T = 1/5 sqrt of "l" (Last part after the T is one fifth to the square root of the letter L)
\[T=\frac{1}{\sqrt{L}}\]
take the reciprocal of both sides \[\frac{1}{T}=\sqrt{L}\]
No Sat, one fifth to the square root of l
then square both sides \[(\frac{1}{T})^2=l\]
OHHHHH ! Was that an example ? lol
ok fine l not L
hold the phone. is it \[T=\frac{1}{\sqrt[5]{l}}\]
fifth root?
in that case take the reciprocal of both sides and raise to the fifth power.
\[\frac{1}{T}=\sqrt[5]{l}\]
\[(\frac{1}{T})^5=l\] \[\frac{1}{T^5}=l\]
Sat, ONE FIFTH like the fraction 1 OVER 5.... its \[T = 1/5 \sqrt{l}\]
ok we try again
\[T=\frac{1}{5\sqrt{l}}\]
take the reciprocal \[\frac{1}{T}=5\sqrt{l}\]
divide both sides by 5 \[\frac{1}{5T}=\sqrt{l}\]
square both sides \[(\frac{1}{5t})^2=l\] \[\frac{1}{25T^2}=l\]
Thanks !! Love the explanation.
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