Question

The heat of fusion for water at its normal freezing or melting temperature is L=333 kJ/kg. How much water remains unfrozen after 50.2 kJ is transferred as heat from 260 g of liquid water initially at its freezing point?

Answer 1

50.2 kJ = 333 kJ/kg * mass of water
mass of water is 0.15075075075075075075075075075075 kg
therefore mass of unfrozen water is 0.10924924924924924924924924924925 kg

Answer 2

good grief.... what's with all the digits? Buy a new calculator? The answer cannot be any more accurate than the original numbers... this ain't math

Answer 3

thanks guys, i almost made the .151 kg my answer