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Like four more problems left...I'm getting sleepy. Make "a" the subject of P = 2(a+b)
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P = 2a + 2b (distribution) P - 2b = 2a (P-2b)/2 = a
lets knock em out
I'll be posting them on a fresh new thread Sat.
\[P=2(a+b)\] \[\frac{P}{2}=a+b\] \[\frac{P}{2}-b=a\]
How are you doing those fractions?
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Jabber lol just click the "equation" button and u can type wat u need to make it clearer
Here's what it looks like when I do it: \[P/2-b=a\]
Ehh close enough lol
I'm wondering how he gets P over 2
Lol
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Same here!
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