Find the inverse of the following matrix.

7 3
4 2

Question

Find the inverse of the following matrix.

7  3
4  2

anonymous · Answer

$$\frac{1}{(7*2)-(3*4)}$$$$\frac{1}{14-12}=\frac{1}{2}$$

anonymous · Answer

Do you know How to find Co-Factors ?

anonymous · Answer

Do u want the ANSWER ? or Should I walk u through the Problem..

anonymous · Answer

Please walk me through the problem. I have no idea where to begin.

anonymous · Answer

Ok

salina · Answer

$$\frac{1}{(a*d)-(b*c)}$$time
[d  -b]
[-c   a]

salina · Answer

$$\frac{1}{(7*2)-(4*3)}$$=1/2

anonymous · Answer

a b
c d 
to find the inverse find the determinant  (ad-bc)
The inverse is 1/(ad-bc) times the matrix   d  -b
                                                                 -c    a
so in this case it is 1/2 [ 2  -3
                                     -4  7  ]
=[ 1  -1.5
   -2   3.5 ]

salina · Answer

1/2 *  [2   -3]       [1 -3/2]
          [-4   7]  =   [-2  7/2]

anonymous · Answer

Thank you very much!

anonymous · Answer

very easy way is $$\left[\begin{matrix}A & B \ C & D\end{matrix}\right]$$

take the determinate 1/(AD-CB) and flip C and B and negate A and D

anonymous · Answer

swap A and D and negate B and C