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Mathematics 21 Online
OpenStudy (anonymous):

use linear approximation to estimate the given number. a.) 2.001^5 b.) tan44degrees

OpenStudy (anonymous):

32.08

OpenStudy (anonymous):

.96

OpenStudy (anonymous):

how did u do that?

OpenStudy (anonymous):

@anliker - I answered the how on your previous post of the 2.001^5 question. Use the same method for the tan(44 degrees)

OpenStudy (anonymous):

For tan(44), your function f(x)=tan(x), f'(x)=sec^2(x), x=44, a=45.

OpenStudy (anonymous):

thank you very much.

OpenStudy (anonymous):

btw...here's the wiki for linear approximation with a good example: http://en.wikipedia.org/wiki/Linear_approximation

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