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use linear approximation to estimate the given number. a.) 2.001^5 b.) tan44degrees
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32.08
.96
how did u do that?
@anliker - I answered the how on your previous post of the 2.001^5 question. Use the same method for the tan(44 degrees)
For tan(44), your function f(x)=tan(x), f'(x)=sec^2(x), x=44, a=45.
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thank you very much.
btw...here's the wiki for linear approximation with a good example: http://en.wikipedia.org/wiki/Linear_approximation
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