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Mathematics 16 Online
OpenStudy (anonymous):

anyone good with graphs ? - attachment below.

OpenStudy (anonymous):

OpenStudy (anonymous):

u sure?

OpenStudy (anonymous):

new one

OpenStudy (anonymous):

new one!

OpenStudy (anonymous):

Just substitue and x and for each equation, which will give you the coresponding y. That is, y = mx + c, substituting random number for x , let's say 2 gives us: y = m2 + c. Since, you have your values of c and m then you can easily equate y with simple maths. e.g one of you questions would be m = 2, c = 5, and thus y = 2*2+5 , or 9. So then you have one coordinate, your original x and your new y (2,9). Do that for 2 points on each equation and you can then draw a straight line across the points to give your graph.

OpenStudy (anonymous):

I'm guessing the answer is where the two lines cross, the question seems to be very vague as to what it's asking us for. You would then just find where they cross and whatever the x and y coodinates are, that's your answer if I'm not mistaken.

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