Question

how to solve this: (2x-3)(3x+2)<0

Answer 1

you can solve this just like solving a normal equation just set the < to an =

Answer 2

\[REVISED: (2x-3)(3x+2)\le0\]

Answer 3

no i cant solve it like a normal equation. The answer is \[-2/3 \le x \le 3/2\]

Answer 4

i dont know how to factor to get the x to be greater than -2/3 and less than 3/2

Answer 5

Yeah, what mercury said

Answer 6

@ heromiles, that doesnt help

Answer 7

I guess you want me to solve it for you....

Answer 8

6x^2+5x-6
-5+-\[-5+-\sqrt{25-4(6)(-6)}/2(6)\]
this comes from the quadratic equation

Answer 9

yes, i need to know how to get the answer i provided

Answer 10

from there you can get your factors and your answers

Answer 11

Mercury it was already factored....

Answer 12

do you HAVE to use the quadratic equation in this?

Answer 13

All he needs to do is separate each binomial into two equations.

Answer 14

Then solve for x

Answer 15

you can factor by foil but i always find using the quadratic equation to be easiest

Answer 16

Case 1 2x-3 <0
2x < 3
x< 3/2

case 2 3x+2 <0
3x< -2
x< -2/3

i.e. -2/3< x < 3/2

Answer 17

i was tring to factor by foil. but i can never get it to work out, because when dividing by a negative number, both signs switch and i cant get x to be greater than and less than

Answer 18

You don't need foil to do this...angel has it

Answer 19

or if you want you can do it angels away. its math you can do it so many different ways and still get the right answer

Answer 20

angel your answer is what i did but is incorrect

Answer 21

Why is it incorrect?

Answer 22

she jumped from having x < for both answers to having <x<

Answer 23

Oh yes, you're right

Answer 24

because x can be between those two there isnt just 1 answer that makes the inequality right

Answer 25

Only the last part was incorrect

Answer 26

yes, i dont understand how to make the jump, no it takes both answers to make the inequality correct

Answer 27

What you do is plot the solutions on a number line

Answer 28

i see what outkast is saying for case two the sign needs to be switched

Answer 29

No it doesn't

Answer 30

case 2 3x+2 <0
3x< -2
x< -2/3
x > 2/3
i.e. 2/3< x < 3/2

Answer 31

Why do you need to switch the sign? You only need to do that if multiplying or dividing by a negative

Answer 32

yes but he gave us the answer to the problem first. In order for it to mach x has to be greater than -2/3 meaning the sign has to turn

Answer 33

he probably miss typed something

Answer 34

I don't agree with angel's solution

Answer 35

I agree fully with her solution because that's what i got when i did a quadratic equation for it

Answer 36

Hmmm, well maybe your approach was better after all. I'll keep that in mind next time

Answer 37

I wish I could give you a medal, but I can't

Answer 38

lol did you write down the answer correctly? because that -2/3 should be a 2/3 could very well be a miss print

Answer 39

even i think its a miss print.

Answer 40

it's definitely supposed to be -2/3 without question

Answer 41

well its wrong lol there is no possible way for you to get that answer from that inequality

Answer 42

Yes, I've confirmed that the solution is indeed x<-2/3 or x> 3/2 which is what I had originally

Answer 43

well see that is very different from the answer you put of -2/3x<3/2

Answer 44

-2/3<x<3/2

Answer 45

I never put that as an answer

Answer 46

http://www.wolframalpha.com/input/?i=solve%286x^2-5x-6%3E0%2Cx%29

Answer 47

I confirmed it using my own math, TI-Nspire and Wolfram Alpha confirms it

Answer 48

no i cant solve it like a normal equation. The answer is
−2/3≤x≤3/2 3rd post lol but okay

Answer 49

Okay, I had the sign backwards, you're right

Answer 50

I have posted the steps to solve this problem at:
http://www.oojih.com/show/algebra/inequalities/

scroll down to comment section to see your question posted and explanations.