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Mathematics 17 Online
OpenStudy (anonymous):

instructions on how to do this? or answers? :D (picture below)

OpenStudy (anonymous):

OpenStudy (anonymous):

This is just the inverse function: 1/12x

OpenStudy (anonymous):

exactly

OpenStudy (anonymous):

correction 1/12x+4

OpenStudy (anonymous):

manjoeseo, we seem to be getting the same!

OpenStudy (anonymous):

what??

OpenStudy (anonymous):

OpenStudy (anonymous):

heck no. \[f^{-1}(x)=\frac{x-4}{12}\]

OpenStudy (anonymous):

@scilaaax3 answer to first one is \[\frac{x-4}{12}\]

OpenStudy (anonymous):

i know i got it wrong :( i already got two wrong. i cant get anymore wrong...

OpenStudy (anonymous):

\[f^{-1}(-4)=9\]

OpenStudy (anonymous):

OpenStudy (anonymous):

answer to 2.png is 9

OpenStudy (anonymous):

OpenStudy (anonymous):

answer to 1.png is \[\frac{x+8}{6}\]

OpenStudy (anonymous):

OpenStudy (anonymous):

is this x+6 over -6 ?

OpenStudy (anonymous):

The giveaway here is 8 goes to 0 and 0 to -8

OpenStudy (anonymous):

\[\frac{6-x}{6}\]

OpenStudy (anonymous):

satellite, give an example please.

OpenStudy (anonymous):

OpenStudy (anonymous):

3more guys !1!!!!!!

OpenStudy (anonymous):

here are the steps. put \[y=-6x+6\] switch x and y to get \[x=-6y+6\] and solve for y via \[x-6=-6y\] \[\frac{x-6}{-6}=\frac{6-x}{6}=y\]

OpenStudy (anonymous):

OpenStudy (anonymous):

i need for 3

OpenStudy (anonymous):

\[f(x)=\frac{1}{2}x+8\] \[y=\frac{1}{2}x+8\] \[x=\frac{1}{2}y+8\] \[x-8=\frac{1}{2}y\] \[y=2x-16\] is your answer

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