Mathematics
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OpenStudy (anonymous):
instructions on how to do this? or answers? :D (picture below)
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OpenStudy (anonymous):
OpenStudy (anonymous):
This is just the inverse function: 1/12x
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
correction 1/12x+4
OpenStudy (anonymous):
manjoeseo, we seem to be getting the same!
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OpenStudy (anonymous):
what??
OpenStudy (anonymous):
OpenStudy (anonymous):
heck no.
\[f^{-1}(x)=\frac{x-4}{12}\]
OpenStudy (anonymous):
@scilaaax3 answer to first one is
\[\frac{x-4}{12}\]
OpenStudy (anonymous):
i know i got it wrong :( i already got two wrong. i cant get anymore wrong...
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OpenStudy (anonymous):
\[f^{-1}(-4)=9\]
OpenStudy (anonymous):
OpenStudy (anonymous):
answer to 2.png is 9
OpenStudy (anonymous):
OpenStudy (anonymous):
answer to 1.png is
\[\frac{x+8}{6}\]
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OpenStudy (anonymous):
OpenStudy (anonymous):
is this x+6 over -6
?
OpenStudy (anonymous):
The giveaway here is 8 goes to 0 and 0 to -8
OpenStudy (anonymous):
\[\frac{6-x}{6}\]
OpenStudy (anonymous):
satellite, give an example please.
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OpenStudy (anonymous):
OpenStudy (anonymous):
3more guys !1!!!!!!
OpenStudy (anonymous):
here are the steps. put
\[y=-6x+6\] switch x and y to get
\[x=-6y+6\] and solve for y via
\[x-6=-6y\]
\[\frac{x-6}{-6}=\frac{6-x}{6}=y\]
OpenStudy (anonymous):
OpenStudy (anonymous):
i need for 3
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OpenStudy (anonymous):
\[f(x)=\frac{1}{2}x+8\]
\[y=\frac{1}{2}x+8\]
\[x=\frac{1}{2}y+8\]
\[x-8=\frac{1}{2}y\]
\[y=2x-16\] is your answer