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solve log (x-1) + Log 4=2
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You can rewrite sum of two logs as one log by multiplying the function
Ok, umm, so you would multiply the (x-1) and the 4?
(x-1)4=100 4x-4=100 x=(100+4)/4 x= 26
wow! How did u get 100?
\[\text{Log}[a]+\text{Log}[b]=\text{Log}[a*b]\]
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U do not go (x-1)4= 4x-4? Where did the 100 come in?
Let me walk through you, based on my post above \[\text{Log}[(x-1)(4)]=2\] \[\text{Log}[(4x-4)]=2\] Now change that to exponential form, \[\text{Log}_ba=c\space \text{ }\space \text{--}> b^c=a\] 10^2=4x-4 100=4x-4
i will look and see if i got it
ok, that part makes sense. so the next step is to...?
oh, i see it.
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