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OpenStudy (anonymous):
Please tell me how to factor to solve: (2x-3)(3x+2)≤ 0. The answer to this equation is (-2/3) ≤ x ≤ (3/2)
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OpenStudy (anonymous):
how it's solved is by separately solving the binomials for the inequality like so... 2x-3<0 2x<3 x<3/2 and 3x+2<0 3x<-2 x<-2/3 and since the inequality is between -2/3 and 3/2 we arrive at \[-2/3\le x \le3/2\]
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