A number y varies inversely as the square of x. If y = 2 when x = 6, what is y when x = 3?

Question

anonymous · Answer

The equation is y=k/x^2

So, just plug stuff in .Do you want me to do it out for you?

anonymous · Answer

or, here:
2=k/36
Solve for K.

Then plug in what you get for K, and what X is, and solve for Y.

anonymous · Answer

yes please

anonymous · Answer

Alright. So, for the first part:
2=k/36
multiple both sides by 36 in order to get rid of the fraction.
this leaves you with:
72=K

Got it so far?

anonymous · Answer

yes

anonymous · Answer

Then you want to plug in K and X into the new equation. It's the SAME equation as before, so that's easy :]

y=k/x^2
y=72/9
Just divide and you get:
y=8

Hope that helped! Do you need any more help on this?

anonymous · Answer

no thanks! thanks so much :)

anonymous · Answer

No problem! Feel free to grab me if you need anything else, hon'.