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What is i^84? A. -i B. i C. -1 D. 1
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1
\[i^{84}=i^{4\cdot21}=(i^4)^{21}=1^{21}=1\]
What about finding the equivalent to \[\sqrt{-121}\] ?
11*11=121 so \[\sqrt{-121}=11i\]
- will be (i^2)^42 =(-1)^42 =((-1)^2)^21 =(1)^21 =1
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yes
the definition of \(i\) is that \[i=\sqrt{-1}\]hence \[i^{84}=(i^{2})^{42}=(-1)^{42}=1\]
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