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For a simple function like y=x If there is a hole at x=0 would the limit as x approaches 0 exist? Or would you just round it to 0?
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Check the limit of the function as x approaches 0 from the right and check the limit of the function as x approaches 0 from the left. If these two limits are equal, then the limit exists. For y = x: lim x->0+ x = 0 lim x->0- x = 0 lim x->0 x = 0
So despite a hole in the graph the limit would still be 0?
Yes, that is correct.
thanks!
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