Ok I have no clue what I did. Eh gave it a try. I had to make "t" the subject of this formula:

S=(1/2)(a)(t^2)

2S/a = t^2

(t^2)^1/2 = (2S/a)^1/2

t = (2S/a)^1/2'

I dont even know if I did it right, if so can yall help a girl out.

Question

Ok I have no clue what I did. Eh gave it a try. I had to make "t" the subject of this formula:

S=(1/2)(a)(t^2)

2S/a = t^2

(t^2)^1/2 = (2S/a)^1/2

t = (2S/a)^1/2'

I dont even know if I did it right, if so can yall help a girl out.

anonymous · Answer

when u square root a variable u have to consider the possibility that the answer may have been negative so it should b 
$$t=\pm \sqrt{2s/a}$$ 
other than that i think its fine

anonymous · Answer

Yep! That's completely right. The in order to get rid of the squared term you just square root it.

anonymous · Answer

Ohhh okay, thanks guys.