The problem is a^2-2ab-3b^2, the chapter is on Polynomials and Factoring, Here is my work. Can you please tell me if it is right, or where I might of went wrong?

a^2-2ba-3b^2 3b-1b=-2b
(a-1b)(a+)
F=a^2 O=3a I= -1ba L= -3b
a^2+3a-1ba-3b

Question

The problem is a^2-2ab-3b^2, the chapter is on Polynomials and Factoring, Here is my work. Can you please tell me if it is right, or where I might of went wrong?

a^2-2ba-3b^2           3b-1b=-2b
(a-1b)(a+)
F=a^2  O=3a   I= -1ba   L= -3b
a^2+3a-1ba-3b

myininaya · Answer

what are you trying to do?
factor?
Ax^2+Bx+C

A=1
B=-2b
C=-3b^2

Find two factors of A*C that add up to be B
A*C=1(-3b^2)=-3b^2=-3b(b)
B=-2b=-3b+b

so we replace -2ab with -3ab+ab and we have

a^2-3ab+ab-3b^2
now factor by grouping

a(a-3b)+b(a-3b)
(a-3b)(a+b)

anonymous · Answer

The directions are:
Factor completely Remember to look first for a common factor. Check my multiplying. If a polynomial is prime, state this.

myininaya · Answer

any questions?

anonymous · Answer

Yeah, why is mine the wrong way? And to me it is all confusing, where did you get-2ab?

anonymous · Answer

why not b and c?

myininaya · Answer

what?

myininaya · Answer

we have Aa^2+Ba+C

what is A=
what is B=
what is C=

now we want to find two factors of A*C that multiplied to be A*C and add up to be B.