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OpenStudy (anonymous):
HELP ! I got stuck lol. Write as a single fraction: 5x / (x-4) + 3x-2 / (x+4)
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OpenStudy (anonymous):
Oh step by step plz lol
OpenStudy (anonymous):
Common denominator (x+4)(x-4) = x^2 -16 5x (x+4) + (3x-2)(x-4) \[5x ^{2} + 20x + 3x ^{2} - 6x + 8\] \[8x ^{2} + 14x + 8\] So \[(8x ^{2} + 14x + 8)\] over \[x^{2} - 16\]
OpenStudy (anonymous):
Thank you !
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