Question

HELP ! I got stuck lol. Write as a single fraction:

5x / (x-4) + 3x-2 / (x+4)

Answer 1

Oh step by step plz lol

Answer 2

Common denominator (x+4)(x-4) = x^2 -16

5x (x+4) + (3x-2)(x-4)

\[5x ^{2} + 20x + 3x ^{2} - 6x + 8\]

\[8x ^{2} + 14x + 8\]

So \[(8x ^{2} + 14x + 8)\] over \[x^{2} - 16\]

Answer 3

Thank you !