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Show that log(base a)x=(log(base b)x)/(log(base b)a) (Hint: take "a" to the power of both sides. On the left side of the equation you will just get x, and on the right side you'll get "a" to that fraction there, but now replace a with b^(log(base b)a). Sorry for the notation. Thank you for viewing. I hope someone has a clue how to do this...
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since we have y=log(basea)x and y=(log(baseb)x)/(log(baseb)a) then log(basea)x=(log(baseb)x)/(log(baseb)a)
cool!?
Ice Cold!
nice
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Thank You myininaya! Not even my tutor who has tutored this course 9 times could figure this problem out.
lol
goodnight i go to sleep
have a great night. Thank you
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