Solution A is 10% sugar while solution b is 30% sugar. A chemist have 60-liter mixture of solutions A and B with 18% sugar. how many liters of each solution should he use?

Question

Solution A is 10% sugar while solution b is 30% sugar. A chemist have 60-liter mixture of  solutions A and B with 18% sugar. how many liters of each solution should he use?

anonymous · Answer

I need the formula also plsss

anonymous · Answer

sorry to interput but is anyone good with inverse functions? :?

trancenova · Answer

C1V1=C2V2
Where '2' is the final solution

C2V2 = C1V1 + C3V3
(we don't know V1 and V3)
0.18x60=0.3xV1+0.1xV3
V1+V3=60
V1=60-V3
0.18x60=0.3(60-V3)+0.1V3
0.18x60=-0.3V3 +18 + 0.1V3 
0.18x60=-0.2V3 +18 
0.18x60-18 = -0.2V3
10.8 + 18 =-0.2V3
-7.2 = -0.2V3
7.2 = 0.2V3
7.2/0.2 =V3
V3= 7.2/0.2 =36
10% solution (A) needs 36L in the 60L to make a 18% soln.
So you need 36L of A and 24L of B.

anonymous · Answer

thanks for the help TraceNova Group Lifesaver