can anyone please show me the steps to solve this problem :) 3=x*3^4 but in expotenetial form :)
\[3=x\times 3^4\]?
yes :)
Sorry, but you need to clarify a bit here.. Is the equation really this: \(3=x\cdot3^4\) Or is it this? \(3 = (x\cdot3)^4\)
would u like to see the whole question ?
Yes, that would be helpful.
if it is the one i posted, divide both sides by \[3^4\] then simplify then take the cube root
divive both by 29 ?
i got 0.103=x
well actually 3^4=81 but yes that is the idea
Oh, ok. So you have: \[3 = x\cdot 3^4\]\[\implies x = \frac{3}{3^4} = \frac{1}{3^3} = \frac{1}{27}\]
oh dear forget decimals
what polpak said. hello polpak!
Decimals are like calculators. To be avoided as often as possible.
oh sorry i did 3^3
oh so how do you put 1/27 in expotential form ? thats what i need help with ; i get the whole precess now :) thanks much it was very helpful ;' so how to put in expotentail form?
Oh. exponential form.. \[\frac{1}{3^3} = 3^{-3}\]
Just have to turn the power in the denominator into a factor with a negative exponent.
ohhh! :D got it ! thanks soo much :) and everything you said i wrote in noters :) thanks again .
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