Find h(f(x)), in terms of x for the following functions, given that: f(x)= x^2 + x h(x)= x/1-x
Alright, let's see if I remember how to do these... ready to work on this together?
yes
h(f(x)) means plug the function f(x) into the function h(x) as the input. So, h(f(x)) = h(x^2+x)...
Replace x in the h(x) function with x^2+x :)
Alright, first thing we want to do is understand what h(f(x)) means.
What this means is "do f(x) first, and then plug that into h(x)"
Does that make sense?
yeah so i get x^2+x/1-(x^2+x)
Perfect.
but then how would i simplify it?
I'll have to grab some pen and paper. I'll be right back.
you don't really need to much. best you can get is\[(x^{2}+x)/(1-x-x^{2})\]after distributiong the negative on the bottom
the denominator doesn't factor, so you can't go any further.
also, did my answer to your other problem help, jerni?
Yep, mtbender's correct. It *can* be modified a bit, but this is as condensed as we can make it.
personally, i'd leave it without distributing the negative. needless "simplification" when it doesn't get you anything is just a waste of time and opens the door for errors. :)
yes it did thank you:)
my pleasure. :)
ah i get it now thank you guys so much!
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