4w^2 + 21w + 5 factor medals will be given
(5 + w) (1 + 4 w) == 0
@Plshlpme: Do you wanna learn how to solve this?
I always want to learn...but I go through steps on my assignment and I am still confused! :(
Sure! Do you know about the quadratic equation?
a little I just don't understand it too much. I try so hard to learn algebra and it is the one thing I can not conquer.
It's ok! It was tricky for me at first. Just gotta have someone explaining all the steps.
The formula is: -b + and - squareroot(b squared - 4ac) all divided by 2a
Now, do you know where we get our a,b,c from?
BTW, I'm answering other questions at the same time and the site keeps freezing, so if you lose me, just post here so that I can get a notification and find your question.
no.
Alright, cool. Here we go: Your original question was:
4w^2 + 21w + 5
ook that's fine.
To make it less scary, we can change our w's into x's. 4x^2 + 21x + 5
The A value is always the number in FRONT of the x^2. The B is always the number in front of the x. And C is always that poor number at the end.
An important note: x^2 does NOT have a zero in front, but instead, there's an invisible 1. So it's 1x^2. But in this instance, we're working with 4x^2 + 21x + 5 So just keep that fact in mind for the future. So, what is our A,B,C for this question?
If it doesn't make sense, do let me know. I don't want to confuse you.
that kind of makes sense.
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