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Triangles ABC and LMN are given such that AB = 24, BC = 20, and AC = 40 LM = 6, MN = 5, and LN = (3a + 1) To be similar, which should be the value of a? Answer 6 5 4 3
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If ABC and LMN are similar, then basically one is a "blown up" version of the other. We have to match up the sides so that there is a single number we can multiply the lengths by to get the other set. For example, LM = 6 and AB = 24, so if we multiply LM by 4, we get 24. Also, 5*4 = 20, so 4 works for MN and BC. To get LN and AC to match up, then, we have to multiply LN by 4 to get 40. We get \[4(3a+1) = 40\]which has the solution a = 3.
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