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in calculus, is average velocity same as the average rate of change?
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average rate of change of position, to be exact
so if the question asks: the displacement of particle moving in a straight line is given this function, and i need to find the average velocity over a time interval, i just need to find the derivative of f(x)?
dertivative of f(x) gets you instantaneous velocity, not average velocity over time interval
That will get you average velocity from x2 to x1 \[\frac { f(x_2)-f(x_1)}{x_2-x_1}\]
oh okay. Thank you so much!
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Here's a nice fact you might like: If a function is continuous on [a, b] and differentiable on (a, b) For some c \in (a, b) \[f'(c) = \frac{f(b) - f(a)}{b - a}\]
MVT?
yeah
u should b a fan of me :)
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