Question

2H initially unfluxed inductor.V(t)=?(see attachment)

Answer 1

I found V(t)=4[u(t)-u(t-2)-u(t-6)+u(t-8)

Answer 2

V = L di/dt

Answer 3

so the gradient of the straight lines are 2, the inductor is 2H

so V=4V

Answer 4

so v should be 4V between 0 and 2 seconds, and -4V between 6 and 8seconds

Answer 5

and it should be zero between 2 and 6 seconds

Answer 6

looks to be right

u(t) starts it at 4V , then -u(t-2) brings it to zero at t=2 , the -u(t-6) brings it to -4V at t=6 and +u(t-8) brings it to zero at t=8.