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OpenStudy (anonymous):
u know completing squares ?
OpenStudy (anonymous):
i could give u the answer... but working on it will be much better
OpenStudy (anonymous):
i dont know how to do it
OpenStudy (anonymous):
ok i'l teach you
OpenStudy (anonymous):
its easy all u have to do is to make squares
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OpenStudy (anonymous):
look at the eq. u will find terms in x^2 ,xy and x so how about if we take 5x common out of the first two expressions 5x^2 - 15xy try that!
OpenStudy (anonymous):
ok now i was wrong bfor u cant do it by cmpleting squares sry but my above reply is right
OpenStudy (anonymous):
okay hold on one sec
OpenStudy (anonymous):
now when u take 5x common it becomes 5x(x - 3y) and now the problem is with .... the left out .. So u tell me wt taking common will help us to get x-3y in the other part
OpenStudy (anonymous):
what do you mean
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OpenStudy (anonymous):
but the second have the only common is 5
OpenStudy (anonymous):
i'm talking about +45y-15x
OpenStudy (anonymous):
what if i take -15 common then -> -15 (x-3y)
so the whole eq becomes 5x(x-3y) - 15 ( x- 3y)
then -> (x-3y)(5x-15)
(x-3y)(5x-15)
5(x-3)(x-3y)