Assume "w" is the generic constant that represents the weight density of the liquid. Given this picture, what is the amount of Force acting upon flat, square object?

Question

Assume "w" is the generic constant that represents the weight density of the liquid.  Given this picture, what is the amount of Force acting upon flat, square object?

amistre64 · Answer

attachment

saifoo.khan · Answer

10+

amistre64 · Answer

generic units of measure as well

anonymous · Answer

i'm a bit puzzled - doesn't it depend on the volume of liquid above the square?

amistre64 · Answer

it does.  but assume the pressure is focused on the face of the square and the downward force is negligible ... does tha tmake sense?

amistre64 · Answer

When I answered it on me test I set up a double integral ... calculus1 class mind you ...

amistre64 · Answer

$$\int_{0}^{4}\int_{0}^{4}(8-y)w\ dxdy$$

anonymous · Answer

i see -makes sense

amistre64 · Answer

i thought so :)  but the teacher asked me why I did the extra step, I spose the single would have been:

$$\int_{0}^{4}4(8-y)w\ dy$$
$$\int_{0}^{4}(32-4y)w\ dy$$

anonymous · Answer

lol - now i'm really stretching my memory - but looks good to me

anonymous · Answer

my grandson's just arrived - got to take him to cricket - later