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Mathematics 19 Online
OpenStudy (anonymous):

confusing :/ help ? ( attachment below)

OpenStudy (anonymous):

OpenStudy (anonymous):

the total no. of combinations are = 12*12*4 = 576

OpenStudy (anonymous):

it was wrong ...

OpenStudy (anonymous):

OpenStudy (anonymous):

13*4*13 maybe?

OpenStudy (anonymous):

:( ?

OpenStudy (anonymous):

sorry, do you have your math book? that may help

OpenStudy (anonymous):

no is online, but why do you think 13*4*13? explain >?

OpenStudy (anonymous):

there are 13 possible numbers than can be in the first digit. There are 4 possible numbers for the second, and again 13 for the third digit. I looked this idea online, and it also states you would just multiply the number of possible numbers.

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